News Update
Calculatiopn of Efficiency
ABSOLUTE FILTERS
| FILTER SERIAL NO. | OUTLET READING AFTER FILTER FOR 0.3 MICRONS (Y) | EFFIENCY, E=(X-Y) x100/X | REMARKS |
|---|---|---|---|
| 1 | 4 | E=(427233-4)/427233=99.99% | OK |
| 2 | 1 | E=(427233-1)/427233=99.99% | OK |
| 3 | 7 | E=(427233-7)/427233=99,99% | OK |
| 4 | 3 | E=(427233-3)/427233=99.99% | OK |
NOTE:- ALLTHE FILTERS WERE SERIALLY NUMBERED &TESTED. TEST REPORT IS PASTED ON FILTER ITSELF.
Selection of filter media
(A) Rated capacity, Where,
Q = V xA,
V= RFV, Rough Face Velocity, as measured, FPM, ( Feet per Minute
A= Filter face area, Sq. Ft,
V= RFV, Rough Face Velocity, as measured, FPM, ( Feet per Minute
A= Filter face area, Sq. Ft,
(B) I.P.D Initial Pressure Drop, Where,
P= (P2- P1), mm WG
P1= Pressure at air entry side of filter , mm WG
P2= Pressure at air exit side of filter, mm WG
P1= Pressure at air entry side of filter , mm WG
P2= Pressure at air exit side of filter, mm WG
(A) Selection of media
- Pleat depth, d= 50 mm
- Pleat size, = 100mm
- No of pleats per ft = 11 folds per RFT.
- Calculations for filter size, 600x 600 x50 mm
- No of pleats (Folds ) in 600 mm = 0.600 *11*3.28=21.64 nos. say 22 nos
- Allowing for one fold at each end of media extra for clamping/ fixing to frame.
- No of folds in panel = 24 nos.
- Length of media =24x0.100= 2.4 RM or 2.4x 3.28 = 7.87 RFT
- Area of filter media = width of panel x Running Length of media
- = 0.600 M x 2.4 RM = 1.44 M3, or 1.44 x 3.28x3.28
- = 1.44 x 10.76 sq ft
- = 15.49 sq. ft.
We select HIGH LOFT FILTER MEDIA , quality 269 F, polyester , having Air Permeability of 7000 CMH/ SQ. M at 5.0 mm W G.
Face Velocity
Required face velocity
Required face velocity
= 7000/60x60 : 0,600x0.600
= 1.95 :.36
= 5.27 m/s
= 500 FPM ( feet per minute )
= 500 : 3.28 X 60 = 2.54 m/s
Hence media selected is ok
= 1.95 :.36
= 5.27 m/s
= 500 FPM ( feet per minute )
= 500 : 3.28 X 60 = 2.54 m/s
Hence media selected is ok
NUMBER OF PLEATES
- 1.0 : Input information
Area to be provided, A - Ft2
VOLUME of air flow required, V- FT3, at initial pressure drop , P1 - 2.0 size of filter panel, say 24”x 24”X6”
- 3.0 area=24x 24/144=4 sq. ft
- 4.0 filtration area = 55 sq.ft , or 55/(3.28X3.28)= 5.11 sq. mt
approximate no of pleats
filtration area= 5.. sq. mt
width of panel= 24” or 610 mm or 0.61 mt
area = width x runnining length of media,L, - 5.11 = 0.61 x L
There fore , L= 5.11/0.61=8.38 mt
Depth of filter panel= 6” or 0.1524 mt ,
Approximate no of spacers, S , required=L/ H or 8.38/ 0.1524= 55 nos
Approximate no of pleats, N , required= S/2 = 55 / 2 ( FOLDS ) 27 nos
Considering physical width of spacers, no of pleates should = 23 or 24 nos
Selection of filter media
Panel size = 24”x24”x6”(W x H x D )
Filtration area, + 55 sq. ft= 5.11 sq. mt. Rated capacity at 6,5 mm WG,=1700 cmh
=28.34 m3 per min
air permeabilty= 1700 cmh / 5.11 sq. mt=332 mt3/hr/mt2 at 6.5 mm WG quality select 306A a. p= 7500 mt 3/hr/ mt 2 at 5 mm wg
